L\u00f4 \u0111\u1eb9p h\u00f4m nay s\u1ebd chia s\u1ebd ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 si\u00eau ch\u00ednh x\u00e1c v\u00e0 l\u00e3i g\u1ea5p 4 l\u1ea7n s\u1ed1 v\u1ed1n m\u00ecnh b\u1ecf ra. C\u00e1ch soi c\u1ea7u n\u00e0y d\u1ef1a v\u00e0o gi\u1ea3i nh\u00ec v\u00e0 gi\u1ea3i ba \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh c\u1ea7u l\u00f4 \u0111\u1ec1 c\u1ea7n \u0111\u00e1nh trong ng\u00e0y. \u0110\u00e2y l\u00e0 m\u1ed9t c\u00e1ch \u0111\u00e1nh r\u1ea5t hay, anh em c\u00f9ng tham kh\u1ea3o.<\/p>\n
\u0110\u1ec3 \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 b\u1eaft c\u1ea7u \u0111\u1ec1<\/strong><\/em><\/h2>\n<\/p>\n
\u0110\u1ec3 v\u1eadn d\u1ee5ng soi c\u1ea7u h\u00f4m nay ta \u0111i v\u00e0o c\u00e1c b\u01b0\u1edbc t\u00ednh sau<\/strong><\/p>\nB\u01b0\u1edbc 1 :<\/strong><\/h5>\nTa s\u1ebd x\u00e9t gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec v\u00e0 gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba \u0111\u1ec3 soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 ng\u00e0y h\u00f4m nay.<\/p>\n
V\u00ed d\u1ee5 ng\u00e0y : 18\/06\/2024<\/p>\n
\n- Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec : 646<\/strong>08<\/li>\n
- Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba : 086<\/strong>43<\/li>\n<\/ul>\n
B\u01b0\u1edbc 2 :<\/strong><\/h5>\nH\u01b0\u1edbng d\u1eabn soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1.<\/p>\n
Ta g\u1ecdi s\u1ed1 \u1edf gi\u1eefa gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec l\u00e0 : A.<\/p>\n
S\u1ed1 \u1edf gi\u1eefa gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba l\u00e0 : B.<\/p>\n
Ta s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 AB, BA v\u00e0 \u0111\u1ec1 ta s\u1ebd \u0111\u00e1nh ch\u1ea1m A v\u00e0 ch\u1ea1m B.<\/p>\n
\u1ede v\u00ed d\u1ee5 ng\u00e0y 18\/06\/2024 ta c\u00f3 :
\nA = 6
\nB = 6<\/p>\n
V\u1eady ta s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 66 l\u1ed9n 99 v\u00e0 \u0111\u1ec1 ta s\u1ebd \u0111\u00e1nh ch\u1ea1m 6, ch\u1ea1m 9.<\/p>\n
B\u01b0\u1edbc 3 :<\/strong><\/h5>\nTa s\u1ebd \u0111\u00e1nh c\u1eb7p l\u00f4 AB,BA v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B theo t\u1ef7 l\u1ec7 1 : 1 (\u0111\u00e1nh m\u1ed7i con l\u00f4 AB,BA 10 \u0111i\u1ec3m v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B m\u1ed7i con 10k). V\u1edbi ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 h\u00f4m nay<\/strong> ta ch\u1ec9 \u0111\u00e1nh trong v\u00f2ng 1 ng\u00e0y duy nh\u1ea5t, kh\u00f4ng v\u1ec1 th\u00ec ta b\u1ecf lu\u00f4n ng\u00e0y mai l\u1ea1i \u0111\u00e1nh c\u1ea7u t\u01b0\u01a1ng t\u1ef1.<\/p>\nV\u00ed d\u1ee5 :<\/strong> \u1ede ng\u00e0y 18\/06\/2024 ta t\u00ednh \u0111\u01b0\u1ee3c AB=66. Th\u00ec ng\u00e0y 19\/06\/2024 ta \u0111\u00e1nh c\u1eb7p l\u00f4 66 v\u00e0 99 d\u00e0n \u0111\u1ec1 38 con ch\u1ea1m 6 v\u00e0 ch\u1ea1m 9. Xem k\u1ebft qu\u1ea3 ng\u00e0y 19\/06\/2024 ta th\u1ea5y l\u00f4 v\u1ec1 66 (ch\u1ea1m 6) v\u00e0 l\u00f4 66 2 nh\u00e1y.<\/p>\nTr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t : <\/strong>A = B th\u00ec ta b\u1ecf kh\u00f4ng \u0111\u00e1nh ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\nV\u00ed d\u1ee5 :<\/strong> Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec : 85605.<\/p>\nGi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba : 41624.<\/p>\n
Ta th\u1ea5y A = 6 v\u00e0 B c\u0169ng =6. N\u00ean ng\u00e0y h\u00f4m \u0111\u00f3 ta b\u1ecf kh\u00f4ng \u0111\u00e1nh.<\/p>\n
B\u01b0\u1edbc 1 :<\/strong><\/h5>\nTa s\u1ebd x\u00e9t gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec v\u00e0 gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba \u0111\u1ec3 soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 ng\u00e0y h\u00f4m nay.<\/p>\n
V\u00ed d\u1ee5 ng\u00e0y : 18\/06\/2024<\/p>\n
\n- Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec : 646<\/strong>08<\/li>\n
- Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba : 086<\/strong>43<\/li>\n<\/ul>\n
B\u01b0\u1edbc 2 :<\/strong><\/h5>\nH\u01b0\u1edbng d\u1eabn soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1.<\/p>\n
Ta g\u1ecdi s\u1ed1 \u1edf gi\u1eefa gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec l\u00e0 : A.<\/p>\n
S\u1ed1 \u1edf gi\u1eefa gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba l\u00e0 : B.<\/p>\n
Ta s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 AB, BA v\u00e0 \u0111\u1ec1 ta s\u1ebd \u0111\u00e1nh ch\u1ea1m A v\u00e0 ch\u1ea1m B.<\/p>\n
\u1ede v\u00ed d\u1ee5 ng\u00e0y 18\/06\/2024 ta c\u00f3 :
\nA = 6
\nB = 6<\/p>\n
V\u1eady ta s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 66 l\u1ed9n 99 v\u00e0 \u0111\u1ec1 ta s\u1ebd \u0111\u00e1nh ch\u1ea1m 6, ch\u1ea1m 9.<\/p>\n
B\u01b0\u1edbc 3 :<\/strong><\/h5>\nTa s\u1ebd \u0111\u00e1nh c\u1eb7p l\u00f4 AB,BA v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B theo t\u1ef7 l\u1ec7 1 : 1 (\u0111\u00e1nh m\u1ed7i con l\u00f4 AB,BA 10 \u0111i\u1ec3m v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B m\u1ed7i con 10k). V\u1edbi ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 h\u00f4m nay<\/strong> ta ch\u1ec9 \u0111\u00e1nh trong v\u00f2ng 1 ng\u00e0y duy nh\u1ea5t, kh\u00f4ng v\u1ec1 th\u00ec ta b\u1ecf lu\u00f4n ng\u00e0y mai l\u1ea1i \u0111\u00e1nh c\u1ea7u t\u01b0\u01a1ng t\u1ef1.<\/p>\nV\u00ed d\u1ee5 :<\/strong> \u1ede ng\u00e0y 18\/06\/2024 ta t\u00ednh \u0111\u01b0\u1ee3c AB=66. Th\u00ec ng\u00e0y 19\/06\/2024 ta \u0111\u00e1nh c\u1eb7p l\u00f4 66 v\u00e0 99 d\u00e0n \u0111\u1ec1 38 con ch\u1ea1m 6 v\u00e0 ch\u1ea1m 9. Xem k\u1ebft qu\u1ea3 ng\u00e0y 19\/06\/2024 ta th\u1ea5y l\u00f4 v\u1ec1 66 (ch\u1ea1m 6) v\u00e0 l\u00f4 66 2 nh\u00e1y.<\/p>\nTr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t : <\/strong>A = B th\u00ec ta b\u1ecf kh\u00f4ng \u0111\u00e1nh ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\nV\u00ed d\u1ee5 :<\/strong> Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec : 85605.<\/p>\nGi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba : 41624.<\/p>\n
Ta th\u1ea5y A = 6 v\u00e0 B c\u0169ng =6. N\u00ean ng\u00e0y h\u00f4m \u0111\u00f3 ta b\u1ecf kh\u00f4ng \u0111\u00e1nh.<\/p>\n
B\u01b0\u1edbc 2 :<\/strong><\/h5>\nH\u01b0\u1edbng d\u1eabn soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1.<\/p>\n
Ta g\u1ecdi s\u1ed1 \u1edf gi\u1eefa gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec l\u00e0 : A.<\/p>\n
S\u1ed1 \u1edf gi\u1eefa gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba l\u00e0 : B.<\/p>\n
Ta s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 AB, BA v\u00e0 \u0111\u1ec1 ta s\u1ebd \u0111\u00e1nh ch\u1ea1m A v\u00e0 ch\u1ea1m B.<\/p>\n
\u1ede v\u00ed d\u1ee5 ng\u00e0y 18\/06\/2024 ta c\u00f3 :
\nA = 6
\nB = 6<\/p>\n
V\u1eady ta s\u1ebd \u0111\u01b0\u1ee3c c\u1eb7p l\u00f4 66 l\u1ed9n 99 v\u00e0 \u0111\u1ec1 ta s\u1ebd \u0111\u00e1nh ch\u1ea1m 6, ch\u1ea1m 9.<\/p>\n
B\u01b0\u1edbc 3 :<\/strong><\/h5>\nTa s\u1ebd \u0111\u00e1nh c\u1eb7p l\u00f4 AB,BA v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B theo t\u1ef7 l\u1ec7 1 : 1 (\u0111\u00e1nh m\u1ed7i con l\u00f4 AB,BA 10 \u0111i\u1ec3m v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B m\u1ed7i con 10k). V\u1edbi ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 h\u00f4m nay<\/strong> ta ch\u1ec9 \u0111\u00e1nh trong v\u00f2ng 1 ng\u00e0y duy nh\u1ea5t, kh\u00f4ng v\u1ec1 th\u00ec ta b\u1ecf lu\u00f4n ng\u00e0y mai l\u1ea1i \u0111\u00e1nh c\u1ea7u t\u01b0\u01a1ng t\u1ef1.<\/p>\nV\u00ed d\u1ee5 :<\/strong> \u1ede ng\u00e0y 18\/06\/2024 ta t\u00ednh \u0111\u01b0\u1ee3c AB=66. Th\u00ec ng\u00e0y 19\/06\/2024 ta \u0111\u00e1nh c\u1eb7p l\u00f4 66 v\u00e0 99 d\u00e0n \u0111\u1ec1 38 con ch\u1ea1m 6 v\u00e0 ch\u1ea1m 9. Xem k\u1ebft qu\u1ea3 ng\u00e0y 19\/06\/2024 ta th\u1ea5y l\u00f4 v\u1ec1 66 (ch\u1ea1m 6) v\u00e0 l\u00f4 66 2 nh\u00e1y.<\/p>\nTr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t : <\/strong>A = B th\u00ec ta b\u1ecf kh\u00f4ng \u0111\u00e1nh ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\nV\u00ed d\u1ee5 :<\/strong> Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec : 85605.<\/p>\nGi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba : 41624.<\/p>\n
Ta th\u1ea5y A = 6 v\u00e0 B c\u0169ng =6. N\u00ean ng\u00e0y h\u00f4m \u0111\u00f3 ta b\u1ecf kh\u00f4ng \u0111\u00e1nh.<\/p>\n
\nA = 6
\nB = 6<\/p>\n
Ta s\u1ebd \u0111\u00e1nh c\u1eb7p l\u00f4 AB,BA v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B theo t\u1ef7 l\u1ec7 1 : 1 (\u0111\u00e1nh m\u1ed7i con l\u00f4 AB,BA 10 \u0111i\u1ec3m v\u00e0 d\u00e0n \u0111\u1ec1 ch\u1ea1m A, ch\u1ea1m B m\u1ed7i con 10k). V\u1edbi ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 t\u00ednh c\u1ea7u \u0111\u1ec1 h\u00f4m nay<\/strong> ta ch\u1ec9 \u0111\u00e1nh trong v\u00f2ng 1 ng\u00e0y duy nh\u1ea5t, kh\u00f4ng v\u1ec1 th\u00ec ta b\u1ecf lu\u00f4n ng\u00e0y mai l\u1ea1i \u0111\u00e1nh c\u1ea7u t\u01b0\u01a1ng t\u1ef1.<\/p>\n V\u00ed d\u1ee5 :<\/strong> \u1ede ng\u00e0y 18\/06\/2024 ta t\u00ednh \u0111\u01b0\u1ee3c AB=66. Th\u00ec ng\u00e0y 19\/06\/2024 ta \u0111\u00e1nh c\u1eb7p l\u00f4 66 v\u00e0 99 d\u00e0n \u0111\u1ec1 38 con ch\u1ea1m 6 v\u00e0 ch\u1ea1m 9. Xem k\u1ebft qu\u1ea3 ng\u00e0y 19\/06\/2024 ta th\u1ea5y l\u00f4 v\u1ec1 66 (ch\u1ea1m 6) v\u00e0 l\u00f4 66 2 nh\u00e1y.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t : <\/strong>A = B th\u00ec ta b\u1ecf kh\u00f4ng \u0111\u00e1nh ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\n V\u00ed d\u1ee5 :<\/strong> Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i nh\u00ec : 85605.<\/p>\n Gi\u1ea3i th\u1ee9 nh\u1ea5t c\u1ee7a gi\u1ea3i ba : 41624.<\/p>\n Ta th\u1ea5y A = 6 v\u00e0 B c\u0169ng =6. N\u00ean ng\u00e0y h\u00f4m \u0111\u00f3 ta b\u1ecf kh\u00f4ng \u0111\u00e1nh.<\/p>\n